A spring which obeys Hooke's law has a force constant of 160 N/m
ai) Caculate the extension in mm of the spring produced by a force of 4.0 N
Anyone explain how to do this?
- Thanks.
The force constant is a way of saying how strong the spring is. 160 N/m means 160 Newtons needed to stretch it 1 metre. The fact it obeys Hooke's Law means that if 160N stretches it 1m, then 80N would stretch it 0.5m 40N would stretch it 0.25m etc For most springs you would only be able to stretch them a small amount. So if 40N could stretch it 0.25m (250mm) How much does 4N stretch it?
Mathematically that is written as F=kx F is the force need to stretch it a length x and k is the force constant.
Doing it this way is just a case of plugging the numbers in.
How embarrassing. No really it is. Im doing A-level physics.
I wouldn't worry too much. I've done the same myself in the past. (Divided instead of multiplied) Usually the result of being in too much of a hurry to complete a reply and not concentrating on what I'm doing.