D1 maths emergency!

I have a D1 exam tommorow and I still have some unanswered questions. For example how do you draw the line y>1/3x.

Secondly how do draw the lines when the line goes above the scaling of the graph.
For example: http://store.aqa.org.uk/qual/gceasa/qp-ms/AQA-MD01-W-QP-JUN09.PDF

Question 6^

Reply 1

LimeTree.

12

Well..
Y>1/3x

Sub in values of x and y....

sub 1 into x for instance

y=1/3(1) so the point on the graph are (1,1/3)

Thats the only point you'l need as you already know it goes through the origin.. so then just draw a straight line through (0,0) and (1,1/3)

It say Y>1/3x
So shade in the side of the line thats closest to the x axis... easy :smile:

Same with your other question, just plot 2 points and draw a straight line

Hope this helps

Reply 2

H.C. Chinaski

12

Original post by wavey93

I have a D1 exam tommorow and I still have some unanswered questions. For example how do you draw the line y>1/3x.

Secondly how do draw the lines when the line goes above the scaling of the graph.
For example: http://store.aqa.org.uk/qual/gceasa/qp-ms/AQA-MD01-W-QP-JUN09.PDF

Question 6^

y>(1/3)x isn't a line it is a region.
I think you mean the boundary y=(1/3)x; in which case yo simply need to know 2 points on the boundary ...

so when x=0, y= ?

when x= 3, y=?

Now draw a dotted line through these points and shade the correct side of the line.

Reply 3

H.C. Chinaski

12

Original post by wavey93

Secondly how do draw the lines when the line goes above the scaling of the graph.
For example: http://store.aqa.org.uk/qual/gceasa/qp-ms/AQA-MD01-W-QP-JUN09.PDF

Question 6^

Not sure what you mean by the part in bold? The graph of a linear equation is infinitely long. Now of course due to the nature of the variables, negative values may no make sense in context of the question. Having had a cursory glance at the question, it seems that you have enough of the "grid" to show the region defined by the given set of constraints.

Reply 4

wavey93

OP

13

Original post by LimeTree.

Well..
Y>1/3x

Sub in values of x and y....

sub 1 into x for instance

y=1/3(1) so the point on the graph are (1,1/3)

Thats the only point you'l need as you already know it goes through the origin.. so then just draw a straight line through (0,0) and (1,1/3)

It say Y>1/3x
So shade in the side of the line thats closest to the x axis... easy :smile:

Same with your other question, just plot 2 points and draw a straight line

Hope this helps

Thanks!

Reply 5

wavey93

OP

13

Original post by H.C. Chinaski

y>(1/3)x isn't a line it is a region.
I think you mean the boundary y=(1/3)x; in which case yo simply need to know 2 points on the boundary ...

so when x=0, y= ?

when x= 3, y=?

Now draw a dotted line through these points and shade the correct side of the line.