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C3 help :( Is 1/x a function?

The C3 book says the graph for y=1/x isn't a function because x=0 can't be mapped. However, on other websites it says it is a function. Can someone clarify and explain this please?

Also, does a function have a domain where x can be any real number?
Reply 1
it is a function: the domain does not include zero
Reply 2
It is a function
Reply 3
It is a function if you state the domain x not = 0

Going to pretend I did not say this
(edited 12 years ago)
Reply 4
Original post by TenOfThem
It is a function if you state the domain x not = 0

It is not a continuous function


Where isn't it continuous?
Reply 5
:frown:
(edited 12 years ago)
Reply 6
http://www.google.com/imgres?q=1/x&um=1&hl=en&client=safari&sa=N&rls=en&biw=1005&bih=886&tbm=isch&tbnid=cupNYfLfV26bOM:&imgrefurl=http://www.mathsrevision.net/alevel/pages.php%3Fpage%3D13&docid=bYpACciWIHrEbM&imgurl=http://www.mathsrevision.net/alevel/pure/1overx.gif&w=428&h=317&ei=KaOiTqm9OouT8gP94rDaBQ&zoom=1

If you look at this graph, you will see the function 1/x. As the x value gets bigger the y value gets smaller, for example:
1/X=Y
1/1=1
1/10=0.1
1/100=0.01
and so on...

And when X value gets smaller the y value gets bigger:
1/X=Y
1/0.1=10
1/0.01=100
1/0.001=1000
and so on..

When x=0 y=infinity, so it cannot be defined because the number is so big. But it still is a function.
Reply 7
thanks guys. i understand now :smile:

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