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Integral
Hi, please could somebody help me with this integral. I can't remeber anything i have learnt which would give this answer.
∫ 1/(g-kv) dv ...... where g and k are constant
answer is: -1/k ln l g-kv l + c
i get the log bit, just not the -1/k, thanks.
∫ 1/(g-kv) dv ...... where g and k are constant
answer is: -1/k ln l g-kv l + c
i get the log bit, just not the -1/k, thanks.
lucas05
Hi, please could somebody help me with this integral. I can't remeber anything i have learnt which would give this answer.
∫ 1/(g-kv) dv ...... where g and k are constant
answer is: -1/k ln l g-kv l + c
i get the log bit, just not the -1/k, thanks.
∫ 1/(g-kv) dv ...... where g and k are constant
answer is: -1/k ln l g-kv l + c
i get the log bit, just not the -1/k, thanks.
∫ 1/(g-kv) dv
take out a factor of -1/k
-1/k ∫ (-k)/(g -kv) dv.
etc.
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