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Trigonomectric Help

Could anybody help me with this question please?

Using your knowledge of the graph y = sin x, sketch with reasons, the graph of:
y^2 = sin x for 0 ≤x 3∏

Thanks in advance
If you like I can send you a powerpoint that explains how to sketch the graph of y2=f(x)y^2 = f(x). Send me your email by pm if you want it.
Reply 2
The way I would attempt this is to notice that it's the same graph as y= +- (sinx)^1/2

Then differentiate this to get the stationary points which end up being: pi/2, 3pi/2 and 5pi/2 for that range.

You will have to sketch the graph in two parts i.e one part would be +(sinx)^1/2 and the other would be -(sinx)^1/2. What you should also notice is that between pi and 2pi the graph is undefined as you would be taking the square root of a negative.

What you should end up with is a graph that, has two oval-shapes on it.

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