Core 4 question find dy/dx

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x=\frac{ln(y)}{ln(a)}=\frac{1}{ln(a)} \times ln(y)

\frac{dx}{dy}=\frac{1}{ln(a)} \times \frac{1}{y} = \frac{1}{yln(a)}

\therefore \frac{dy}{dx}=yln(a)=a^{x}ln(a)

Or just see the spoiler in my earlier post :smile:

Is it because 1/ln(a) is a constant so

dx/dy = 1/ln(a) * 1/y + 0 * ln(y) = 1/yln(a) ?

(edited 11 years ago)

Is it because 1/ln(a) is a constant so

dx/dy = 1/ln(a) * 1/y + 0 * ln(y) = 1/yln(a) ?

Yeah, 1/ln(a) is just a constant so it just carries straight through :smile:

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