The Student Room Group

A-level maths help!

Hello, I have no idea where to even start with part c of this question. I have gotten the rest right its just part c I am really confused on.
(edited 12 months ago)
Reply 1
Original post by skyeforster15
Hello, I have no idea where to even start with part c of this question. I have gotten the rest right its just part c I am really confused on.


How could you find an expression for the velocity?
Reply 2
Original post by Muttley79
How could you find an expression for the velocity?

I attached a photo.
Reply 3
Original post by skyeforster15
I attached a photo.


You need dy/dx
Reply 4
Original post by Muttley79
You need dy/dx

I still do not get it. Why do you need dy/dx?
Reply 5
Original post by skyeforster15
I still do not get it. Why do you need dy/dx?


To get the velocity ...
Reply 6
Original post by skyeforster15
I still do not get it. Why do you need dy/dx?

If your position vector at any time is r = xi + yj then the velocity vector at that time is v = dr/dt. One component will be (dx/dt)i, but the other component (the j-part) requires dy/dt and hence the chain rule so that you can also express it in terms of dx/dt.
Reply 7
Original post by davros
If your position vector at any time is r = xi + yj then the velocity vector at that time is v = dr/dt. One component will be (dx/dt)i, but the other component (the j-part) requires dy/dt and hence the chain rule so that you can also express it in terms of dx/dt.

They have an expression in part (a) for y in terms of x.
Reply 8
Original post by Muttley79
They have an expression in part (a) for y in terms of x.


Yes - I was reinforcing your point that they're going to need dy/dx as part of the calc. Or have I missed something?
Reply 9
Original post by davros
Yes - I was reinforcing your point that they're going to need dy/dx as part of the calc. Or have I missed something?


They then find dy/dx at x= 0 and it's straightforward after that

Quick Reply

Latest