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Reply 180
Original post by navarre
Can someone please explain to me Hardy-Weinberg, giving me a worked example? I really don't understand it...



you need to remember his four assumptions eg: no mutation, selction etc
the two equations p + q = 1
p2 +q2 + 2pq =1

hope it s hepls in terms of what is required of you....
Reply 181
Original post by narnia123
This is how i did it:
0.33=frequency in london so therefore h=0.33 and H=0.67
Hardy Weinberg = p^2+2pq+q^2
where 2pq = heterozygous
heterozygous = 2(0.67x0.33)
=0.4422
=44%
I hope that makes sense, im crap at explaining things lol (i hope it's right too)


You done a preety good job.....coz I am crap at understanding.... lol
Reply 182
Hi everyone lets get this discussion started one day left before the exam....
any suggestions what may be on the last few question....or any tricks to understand the questions...coz I can't undersatnd what is being asked of me.... plase help...:redface:
Reply 183
Original post by g00d4u

you need to remember his four assumptions eg: no mutation, selction etc
the two equations p + q = 1
p2 +q2 + 2pq =1

hope it s hepls in terms of what is required of you....


I get the equation, I just don't get what do to with it with a question...
Reply 184
Original post by navarre
I get the equation, I just don't get what do to with it with a question...


If they ask you to work out:
allele frequency
p + q = 1
genotype frequency
p2 + q2 +2pq = 1
the percentage of a population that has a certain genotype
this can be tricky!
can be a combination of both and has to be a percentage

look up some of the different examples.... one in the specimen is soo vague.....coz its AQA.....
Reply 185
Original post by navarre
I get the equation, I just don't get what do to with it with a question...


Give an example of a question you don't understand.
I've compiled some key points using previous mark schemes. Hope it helps! :smile:
(edited 11 years ago)
Original post by leeandrewarmstrong
I've compiled some key points using previous mark schemes. Hope it helps! :smile:


Thank you, this looks very useful.
Original post by leeandrewarmstrong
I've compiled some key points using previous mark schemes. Hope it helps! :smile:


I've done that too, some of my points are exactly the same ahah, it really helps!
Original post by leeandrewarmstrong
I've compiled some key points using previous mark schemes. Hope it helps! :smile:



Thank you for sharing this :smile:
Reply 191
does anyone have the mark scheme for the specimen 2009 -2010 and january 2012 paper?
(edited 11 years ago)
Original post by Mina!SS
does anyone have the mark scheme for the specimen 2009 -2010 and january 2012 paper?


Jan 2012: http://www.thestudentroom.co.uk/attachment.php?attachmentid=135846&d=1331386803
Original post by leeandrewarmstrong
I've compiled some key points using previous mark schemes. Hope it helps! :smile:


Unit 5 too please :biggrin: this is very helpful
Original post by Mina!SS
does anyone have the mark scheme for the specimen 2009 -2010 and january 2012 paper?


Specimen paper MS
http://www.thomas-reddington.com/uploads/7/7/8/3/778329/bio_u4_ms_specimen.pdf
Reply 195
Original post by . .
Give an example of a question you don't understand.


This is one:

Sea otters were close to extinction at the start of the 20th century. Following a ban
on hunting sea otters, the sizes of their populations began to increase. Scientists
studied the frequencies of two alleles of a gene in one population of sea otters.
The dominant allele, T, codes for an enzyme. The other allele, t, is recessive and
does not produce a functional enzyme.
In a population of sea otters, the allele frequency for the recessive allele, t, was found
to be 0.2.
6 (a) (i) Use the Hardy-Weinberg equation to calculate the percentage of homozygous
recessive sea otters in this population. Show your working.
Reply 196
Original post by leeandrewarmstrong
i've compiled some key points using previous mark schemes. Hope it helps! :smile:


thankyou ! :d <3
Reply 197
Original post by navarre
This is one:

Sea otters were close to extinction at the start of the 20th century. Following a ban
on hunting sea otters, the sizes of their populations began to increase. Scientists
studied the frequencies of two alleles of a gene in one population of sea otters.
The dominant allele, T, codes for an enzyme. The other allele, t, is recessive and
does not produce a functional enzyme.
In a population of sea otters, the allele frequency for the recessive allele, t, was found
to be 0.2.
6 (a) (i) Use the Hardy-Weinberg equation to calculate the percentage of homozygous
recessive sea otters in this population. Show your working.


The HW equations is p2+2pq+q2=1
p = Dominant allele frequency which is the same as T
q = Recessive allele frequency which is the same as t

Homozygous recessive is qq or tt
Heterozygous is pq or Tt
Homozygous dominant is pp or TT

If t = 0.2 then q must = 0.2
Homozygous recessive is qq or tt so that is 0.2 x 0.2 (0.22) which = 0.04
Reply 198
What's everyones plan for the last 24hr? I think I'm going to split my time to repeating some of the harder exam papers and making sure I have memorised equations and such.
Original post by ecokid
What's everyones plan for the last 24hr? I think I'm going to split my time to repeating some of the harder exam papers and making sure I have memorised equations and such.


Past papers galore tomorrow! go over agriculture crap and make sure i know it,

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