The Student Room Group
Reply 1
What is _/X ? Is that the square root [ sqrt(x) ] ??
Reply 2
lol yeah sqrt(x) sorry
Reply 3
Hello!

integral of x^0.5 from 1 to 4 = [(x^3/2)/(3/2)] from 1 to 4
= 2/3 (x^3/2) from 1 to 4
= 2/3 [(4^3/2) - (1^3/2)]
= 2/3 [(2^3) - 1^3]
= 2/3 (8 - 1)
= 2/3 (7)
= 14/3

love danniella
Reply 4
hello!

Extra bit of explanation...
4^3/2 = (root 4)^3 = 2^3 = 8.

love danniella
Reply 5
Mush
Integral of _/X with respect to x ....limits = 1 and 4. What is the value of the definite integral?

i can get it as far as (2x^1.5)/3 before my logic breaks down. None Calculator question!!!


Integral of _/X with respect to x with limits = 1 and 4

= 2/3 (x^1.5) with limits = 1 and 4
= 2/3 (4^1.5 - 1^1.5)
= 2/3 (8-1)
= 14/3

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