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How to simplify this parametric?

I have the following parametric equations

[br]x=t1t[br]so[br]dxdt=1+1t2[br]also[br]y=t+1t[br]therefore[br]dydt=11t2[br][br]x = t - \dfrac{1}{t}[br]so[br]\dfrac{dx}{dt} = 1+ \dfrac{1}{t^2}[br]also[br]y= t + \dfrac{1}{t}[br]therefore[br]\dfrac{dy}{dt} = 1-\dfrac{1}{t^2}[br]

how would I find dy/dx?
I know it's dy/dt divided by dx/dt
but that would give

Unparseable latex formula:

[br]\dfrac{1-t^-^2}{1+t^-^2}[br]



and that's far too messy to be a proper equation?

TIA
(edited 10 years ago)
Think you need to check your dy/dt.

And "too messy to be a proper equation"? You what?
Original post by Mr M
Think you need to check your dy/dt.

And "too messy to be a proper equation"? You what?


to messy when fully expressed I mean

it comes out to

[br]dydx=11t2÷1+1t2[br][br]\dfrac{dy}{dx} = 1 - \dfrac{1}{t^2} \div 1 + \dfrac{1}{t^2}[br]
Reply 3
as Mr M says the dy/dt is wrong. your dx/dt is fine
Reply 4
How is dy/dt = 1 - 1/t^2 ?
Original post by saberahmed786
to messy when fully expressed I mean

it comes out to

[br]dydx=11t2÷1+1t2[br][br]\dfrac{dy}{dx} = 1 - \dfrac{1}{t^2} \div 1 + \dfrac{1}{t^2}[br]


There is no such thing as "too messy". That expression could be simplified by multiplying by t2t2\displaystyle \frac{t^2}{t^2}.

Don't bother doing that though as it is wrong.
Original post by 0x2a
How is dy/dt = 1 - 1/t^2 ?


Original post by the bear
as Mr M says the dy/dt is wrong. your dx/dt is fine


Woops I forgot the t before 1/t >.<
Original post by saberahmed786
Woops I forgot the t before 1/t >.<


Ok then follow my advice in my previous post.
Reply 8
Original post by saberahmed786
...



If you write dxdt=t2+1t2\frac{dx}{dt} = \frac{t^2+1}{t^2}

and similar for dydx\frac{dy}{dx} they become far easier to divide

especially if you remember the rules for dividing fractions
Original post by TenOfThem
If you write dxdt=t2+1t2\frac{dx}{dt} = \frac{t^2+1}{t^2}

and similar for dydx\frac{dy}{dx} they become far easier to divide

especially if you remember the rules for dividing fractions


Original post by Mr M
Ok then follow my advice in my previous post.


I got it now, thank you :smile:

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