Original post by VeeOMGlob
the curve y=5^(x-1) intersects y=2^x
ive logged both of the sides to get
(x-1)log5=xlog2
but i dont know how id get x on one side, unless i take away xlog2???
ive logged both of the sides to get
(x-1)log5=xlog2
but i dont know how id get x on one side, unless i take away xlog2???
Expand the brackets, rearrange then factor out the x
Original post by VeeOMGlob
the curve y=5^(x-1) intersects y=2^x
ive logged both of the sides to get
(x-1)log5=xlog2
but i dont know how id get x on one side, unless i take away xlog2???
ive logged both of the sides to get
(x-1)log5=xlog2
but i dont know how id get x on one side, unless i take away xlog2???
Expand the LHS of the equation.
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