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Chemistry Homework

4) Ethanol (6.9g) and ethanoic acid (9.0g) were kept at a constant temperature until equilibrium was reached. At this time analysis showed that 3.0g ethanoic acid remained. Determine the value of the equilibrium constant for the reaction:

CH3COOH + CH3CH20H = CH3COOCH2CH3 + H2O

5) Calculate Kc for the equilibrium below if [A] = 0.02 mol dm-3
[B2] = 0.10 mol dm-3 and [AB] = 0.40 mol dm-3

2A + B2 = 2AB

My answer for question 5 is [AB]/[A]2[B2] = [0.16] / [0.0004] [0.10] = 4000 4X105

Please can someone answer and explain asap thankyou so much, am really struggling
:-(
(edited 10 years ago)
Well, first write your equations for kc.

Then, I'll give you a hint for 4. We need the concentration to find kc, so calculate the moles of the reaction at equilibrium.

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