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Angular velocity/speed

pp.png
In this diagram what is omega?
Angular velocity or speed?
Why is the direction of angular velocity perpendicular to plane of rotation?
Original post by Zenarthra
pp.png
In this diagram what is omega?
Angular velocity or speed?
Why is the direction of angular velocity perpendicular to plane of rotation?
omega = 2.pi.f

where: 2.pi = 1 radian = 360o

omega is therefore radians/sec.

Since speed = distance/time and is a scalar quantity (magnitude only), velocity is a vector quantity and therefore also has direction.

The arrow is therefore a direction component so omega for this queston is angular velocity (radians/sec anticlockwise).

V is a tangent to the circumference.
(edited 10 years ago)
Reply 2
Original post by uberteknik
omega = 2.pi.f

where: 2.pi = 1 radian = 360o

omega is therefore radians/sec.

Since speed = distance/time and is a scalar quantity (magnitide only), velocity is a vector quantity and therefore also has direction.

The arrow is therefore a direction component so omega for this queston is angular velocity.


Is there any difference between angular velocity or angular speed?
And why is the direction of angular velocity perpendicular to the plane of rotation like this: http://scripts.mit.edu/~srayyan/PERwiki/images/9/95/AngularKinematics02.png

thanks!
Original post by Zenarthra
Is there any difference between angular velocity or angular speed?
And why is the direction of angular velocity perpendicular to the plane of rotation like this: http://scripts.mit.edu/~srayyan/PERwiki/images/9/95/AngularKinematics02.png

thanks!
just amended original answer.
Reply 4
Original post by uberteknik
just amended original answer.


I understand everything you have said, but i dont understand why the direction of angular velocity is perpendicular to the plane of rotation here:
http://scripts.mit.edu/~srayyan/PERwiki/images/9/95/AngularKinematics02.png
Original post by Zenarthra
Is there any difference between angular velocity or angular speed?
And why is the direction of angular velocity perpendicular to the plane of rotation like this: http://scripts.mit.edu/~srayyan/PERwiki/images/9/95/AngularKinematics02.png

thanks!
Yes the difference is one is a scalar and the other is a vector.

Angular velocity can be measured at any point on the disc and the answer will be the same because it is the rate of change of the angle of rotation with time.

The calculus definition of speed is ds/dt and that if anguar speed dtheta/dt i.e. with t tending to zero, the direction tends towards a tangent to the axis of rotation.
(edited 10 years ago)
Original post by Zenarthra
I understand everything you have said, but i dont understand why the direction of angular velocity is perpendicular to the plane of rotation here:
http://scripts.mit.edu/~srayyan/PERwiki/images/9/95/AngularKinematics02.png
It's a poor depiction, but omega is a tangent to the axis of rotation. In this diagram it is not at all clear that is what is actually meant to be shown.
Reply 7
Original post by uberteknik
It's a poor depiction, but omega is a tangent to the axis of rotation. In this diagram it is not at all clear that is what is actually meant to be shown.


Its more clear in these pictures:
http://www.phys.ttu.edu/~batcam/Courses/semester%201/Labs/UNIT%2016%20ROTATIONAL%20DYNAMICS_files/image026.jpg
http://upload.wikimedia.org/wikipedia/commons/thumb/d/d5/Angular_velocity.svg/250px-Angular_velocity.svg.png
Reply 8
Original post by uberteknik
It's a poor depiction, but omega is a tangent to the axis of rotation. In this diagram it is not at all clear that is what is actually meant to be shown.


Is this true?

http://www.phyziczteacher.com/chap8v.bmp


OK it's a little confusing but it is a shorthand notation. i.e. It simply means that the direction of omega (tangent) is referenced to the axis of rotation together with the +ve direction of that axis.

So the omega arrow (shown in the diagram) is meant to depict the axis of rotation and that axis positive direction and not the actual direction of omega which as I said before is a tangent.
(edited 10 years ago)


From a definition point of view, yes. Because the direction is constantly changing, it can only be correct for dtheta/dt where t is zero.
(edited 10 years ago)
Angular velocity is a pseudo vector. Its direction shows, by definition, the direction of the axis of rotation.
Reply 13
Original post by uberteknik
Are you OK with my expalanation is post #10 ?


Yes, thank you!
Original post by Zenarthra
Yes, thank you!

This kind of definition is absolutely critical for referencing the correct direction of rotation wrt any given orthogonal axis system like that used for aircraft, missiles, gyroscopes, robotics etc.
Reply 15
Original post by uberteknik
This kind of definition is absolutely critical for referencing the correct direction of rotation wrt any given orthogonal axis system like that used for aircraft, missiles, gyroscopes, robotics etc.


Ahh i see, thank you!

On this image, is ar is the centripetal force and a(theta) is the linear acceleration, so the direction of acceleration would be the diagonal arrow?

Is this correct?

http://upload.wikimedia.org/wikipedia/commons/thumb/2/22/Nonuniform_circular_motion.svg/579px-Nonuniform_circular_motion.svg.png
Original post by Zenarthra
Ahh i see, thank you!

On this image, is ar is the centripetal force and a(theta) is the linear acceleration, so the direction of acceleration would be the diagonal arrow?

Is this correct?

http://upload.wikimedia.org/wikipedia/commons/thumb/2/22/Nonuniform_circular_motion.svg/579px-Nonuniform_circular_motion.svg.png


There are two cases to consider:

a) Constant omega (constant angular velocity) where: equal angles are traversed in equal times. Because the velocity vector (tangent) is constantly changing direction and acceleration is defined as the rate of change of velocity, then constant circular motion is in fact a definition of acceleration.

That acceleration (ar) is directed towards the axis center of rotation and since acceleration is a result of a force (Newtons laws), the force producing that acceleration must also be directed towards the axis of rotation. That force is defined as centripetal force and is always perpendicular to the tangential velocity vector.

b) Changing omega or non-uniform circular motion: where the angular speed is not constant. This is depicted in the diagram you posted. To produce that change in angular speed, there must be an additional tangential force acting to either slow or speed up the rotation. This is angular acceleration atheta or d2theta/dt2.

So the vector sum of the centripetal force producing (ar) and the force producing the angular acceleration (atheta) is therefore a resultant force acting in the direction (a) shown in the diagram.
(edited 10 years ago)
Reply 17
Original post by uberteknik
There are two cases to consider:

a) Constant omega (constant angular velocity) where: equal angles are traversed in equal times. Because the velocity vector (tangent) is constantly changing direction and acceleration is defined as the rate of change of velocity, then constant circular motion is in fact a definition of acceleration.

That acceleration (ar) is directed towards the axis center of rotation and since acceleration is a result of a force (Newtons laws), the force producing that acceleration must also be directed towards the axis of rotation. That force is defined as centripetal force and is always perpendicular to the tangential velocity vector.

b) Changing omega or non-uniform circular motion: where the angular speed is not constant. This is depicted in the diagram you posted. To produce that change in angular speed, there must be an additional tangential force acting to either slow or speed up the rotation. This is angular acceleration atheta or d2theta/dt2.

So the vector sum of the centripetal force producing (ar) and the force producing the angular acceleration (atheta) therefore is acting in the direction (a) shown in the diagram.


Great explanation thank you!

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