Yes the difference is one is a scalar and the other is a vector.
Angular velocity can be measured at any point on the disc and the answer will be the same because it is the rate of change of the angle of rotation with time.
The calculus definition of speed is ds/dt and that if anguar speed dtheta/dt i.e. with t tending to zero, the direction tends towards a tangent to the axis of rotation.
It's a poor depiction, but omega is a tangent to the axis of rotation. In this diagram it is not at all clear that is what is actually meant to be shown.
It's a poor depiction, but omega is a tangent to the axis of rotation. In this diagram it is not at all clear that is what is actually meant to be shown.
It's a poor depiction, but omega is a tangent to the axis of rotation. In this diagram it is not at all clear that is what is actually meant to be shown.
OK it's a little confusing but it is a shorthand notation. i.e. It simply means that the direction of omega (tangent) is referenced to the axis of rotation together with the +ve direction of that axis.
So the omega arrow (shown in the diagram) is meant to depict the axis of rotation and that axis positive direction and not the actual direction of omega which as I said before is a tangent.
This kind of definition is absolutely critical for referencing the correct direction of rotation wrt any given orthogonal axis system like that used for aircraft, missiles, gyroscopes, robotics etc.
This kind of definition is absolutely critical for referencing the correct direction of rotation wrt any given orthogonal axis system like that used for aircraft, missiles, gyroscopes, robotics etc.
Ahh i see, thank you!
On this image, is ar is the centripetal force and a(theta) is the linear acceleration, so the direction of acceleration would be the diagonal arrow?
a) Constant omega (constant angular velocity) where: equal angles are traversed in equal times. Because the velocity vector (tangent) is constantly changing direction and acceleration is defined as the rate of change of velocity, then constant circular motion is in fact a definition of acceleration.
That acceleration (ar) is directed towards the axis center of rotation and since acceleration is a result of a force (Newtons laws), the force producing that acceleration must also be directed towards the axis of rotation. That force is defined as centripetal force and is always perpendicular to the tangential velocity vector.
b) Changing omega or non-uniform circular motion: where the angular speed is not constant. This is depicted in the diagram you posted. To produce that change in angular speed, there must be an additional tangential force acting to either slow or speed up the rotation. This is angular acceleration atheta or d2theta/dt2.
So the vector sum of the centripetal force producing (ar) and the force producing the angular acceleration (atheta) is therefore a resultant force acting in the direction (a) shown in the diagram.
a) Constant omega (constant angular velocity) where: equal angles are traversed in equal times. Because the velocity vector (tangent) is constantly changing direction and acceleration is defined as the rate of change of velocity, then constant circular motion is in fact a definition of acceleration.
That acceleration (ar) is directed towards the axis center of rotation and since acceleration is a result of a force (Newtons laws), the force producing that acceleration must also be directed towards the axis of rotation. That force is defined as centripetal force and is always perpendicular to the tangential velocity vector.
b) Changing omega or non-uniform circular motion: where the angular speed is not constant. This is depicted in the diagram you posted. To produce that change in angular speed, there must be an additional tangential force acting to either slow or speed up the rotation. This is angular acceleration atheta or d2theta/dt2.
So the vector sum of the centripetal force producing (ar) and the force producing the angular acceleration (atheta) therefore is acting in the direction (a) shown in the diagram.