The Student Room Group

C3 half angle of TAN proof!

If Sin1/2x= +/- (square root) ((1-cosx)/2)
and Cos1/2x= +/- (square root) ((1+cosx)/2)

Then how does tan1/2x become sinx/(1+cosx)?

Could someone explain the steps of the proof please. Thanks
Reply 1
Original post by Johnpeters
If Sin1/2x= +/- (square root) ((1-cosx)/2)
and Cos1/2x= +/- (square root) ((1+cosx)/2)

Then how does tan1/2x become sinx/(1+cosx)?

Could someone explain the steps of the proof please. Thanks

sin(12x)=±1cos(x)2,cos(12x)=±1+cos(x)2\sin(\frac{1}{2}x) = \pm \sqrt{\frac{1-\cos(x)}{2}}, \cos(\frac{1}{2}x) = \pm \sqrt{\frac{1+\cos(x)}{2}}.

Then tan(12x)=1cos(x)1+cos(x)\tan(\frac{1}{2}x) = \sqrt{\frac{1-\cos(x)}{1+\cos(x)}}. Multiply top and bottom by 1+cos(x)1+\cos(x).
Reply 2
Original post by Smaug123
sin(12x)=±1cos(x)2,cos(12x)=±1+cos(x)2\sin(\frac{1}{2}x) = \pm \sqrt{\frac{1-\cos(x)}{2}}, \cos(\frac{1}{2}x) = \pm \sqrt{\frac{1+\cos(x)}{2}}.

Then tan(12x)=1cos(x)1+cos(x)\tan(\frac{1}{2}x) = \sqrt{\frac{1-\cos(x)}{1+\cos(x)}}. Multiply top and bottom by 1+cos(x)1+\cos(x).


Thanks a lot :smile:
EDIT: Don't you multiply the top and bottom by (squareroot) 1+cos(x)?
(edited 10 years ago)
Reply 3
Original post by Smaug123
sin(12x)=±1cos(x)2,cos(12x)=±1+cos(x)2\sin(\frac{1}{2}x) = \pm \sqrt{\frac{1-\cos(x)}{2}}, \cos(\frac{1}{2}x) = \pm \sqrt{\frac{1+\cos(x)}{2}}.

Then tan(12x)=1cos(x)1+cos(x)\tan(\frac{1}{2}x) = \sqrt{\frac{1-\cos(x)}{1+\cos(x)}}. Multiply top and bottom by 1+cos(x)1+\cos(x).


good explanation.

just wondering why the "plus or minus" is not on the tan ?
Reply 4
Original post by Johnpeters
Thanks a lot :smile:
EDIT: Don't you multiply the top and bottom by (squareroot) 1+cos(x)?

Yes, sorry - I meant "multiply the fraction which is inside the square root", not "multiply the whole expression". Sorry.
Reply 5
Original post by the bear
good explanation.

just wondering why the "plus or minus" is not on the tan ?

Consider when tan(x/2) is positive - it's exactly when x is between 0 and pi, or 2pi and 3pi, or…
Consider when sin(x) is positive - it's exactly when x is between 0 and pi, or 2pi and 3pi, or…
And 1+cos(x) is always positive.
Reply 6
Original post by Smaug123
Consider when tan(x/2) is positive - it's exactly when x is between 0 and pi, or 2pi and 3pi, or…
Consider when sin(x) is positive - it's exactly when x is between 0 and pi, or 2pi and 3pi, or…
And 1+cos(x) is always positive.


thanks for that :wink:

Quick Reply

Latest