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PHYA2 - Optics help?

I have looked at the markscheme for this question and noticed they did 180 - 90- critical angle. Why did they do this? to give the refractive angle?


& If so could someone draw a diagram to show this refractive angle as I cant just picutre the 180 degree angle they are taking 90 and 80 degrees from :frown:


http://filestore.aqa.org.uk/subjects/AQA-PHYA2-W-QP-JUN11.PDF
Original post by AhmedDavid
I have looked at the markscheme for this question and noticed they did 180 - 90- critical angle. Why did they do this? to give the refractive angle?


& If so could someone draw a diagram to show this refractive angle as I cant just picutre the 180 degree angle they are taking 90 and 80 degrees from :frown:


http://filestore.aqa.org.uk/subjects/AQA-PHYA2-W-QP-JUN11.PDF

you haven't posted a link to the markscheme...

have you remembered the rules?
every time a ray comes to a boundary you take the normal to the boundary at that point and take angles from there... this may mean you're measuring/calculating angles relative to different directions at different points on the rays path.

optics.PNG

θ is being measured relative to a horizontal normal
the critical angle 80 is being measured relative to a vertical normal
Reply 2
Original post by Joinedup
you haven't posted a link to the markscheme...

have you remembered the rules?
every time a ray comes to a boundary you take the normal to the boundary at that point and take angles from there... this may mean you're measuring/calculating angles relative to different directions at different points on the rays path.



θ is being measured relative to a horizontal normal
the critical angle 80 is being measured relative to a vertical normal


Beaut, Ive spotted the angle due to your diagram thanks a lot :smile:

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