Can't get my head around this question any help would be much appreciated: Methanol can be synthesised from methane and steam by a process that occurs in two stages: Stage 1: CH4+H2O<-->3H2+COdeltaH=+206KJmol Stage 2: CO+2H2<-->CH3OH delta H=-91KJmol Question: Explain why in stage 1 a higher yield of hydrogen and carbon monoxide is not obtained if the pressure is increased and Stage 2 is carried out at a compromise temperature of 500K by considering what would happen at higher and lower temperatures, explain why 500K is a compromise temperature
Can't get my head around this question any help would be much appreciated: Methanol can be synthesised from methane and steam by a process that occurs in two stages: Stage 1: CH4+H2O<-->3H2+COdeltaH=+206KJmol Stage 2: CO+2H2<-->CH3OH delta H=-91KJmol Question: Explain why in stage 1 a higher yield of hydrogen and carbon monoxide is not obtained if the pressure is increased and Stage 2 is carried out at a compromise temperature of 500K by considering what would happen at higher and lower temperatures, explain why 500K is a compromise temperature
Have you studied Le Chatelier's principle as applied to equilibria?