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Calculus of inverse trig

Hi, I've got this question that's got me stumped. How do I show, given
y=arctan(1+x1x)y=\arctan (\frac{1+x}{1-x})
that
dydx=11+x2\frac {dy}{dx}=\frac{1}{1+x^2},
and hence show that
arctan(1+x1x)arctanx=π/4\arctan (\frac{1+x}{1-x})-arctanx=\pi/4 for x<1
Thanks
tany = (1+x)/(1-x)

I think that's the step you're probably struggling to recognise :smile:
Reply 2
Original post by EconFan_73
tany = (1+x)/(1-x)

I think that's the step you're probably struggling to recognise :smile:


I've got that, but I wasn't sure what to do from there. I recall integrating both sides at this step but that doesnt seem to lead me anywhere
Original post by foorganders
I've got that, but I wasn't sure what to do from there. I recall integrating both sides at this step but that doesnt seem to lead me anywhere


Try differentiating the LHS of what you're trying to show. What does it equal? Hence the original expression is....
Reply 4
Original post by ghostwalker
Try differentiating the LHS of what you're trying to show. What does it equal? Hence the original expression is....


I'm not sure which part you mean
Original post by foorganders
I'm not sure which part you mean


The arctan(1+x1x)arctanx\arctan (\frac{1+x}{1-x})-arctanx


Edit: LHS stands for "left hand side" - fairly standard and endemic in maths.
(edited 9 years ago)
Reply 6
Original post by ghostwalker
The arctan(1+x1x)arctanx\arctan (\frac{1+x}{1-x})-arctanx


Edit: LHS stands for "left hand side" - fairly standard and endemic in maths.


I know that... I thought you meant something in the first part, which is the bit I'm focused on for now
Original post by foorganders
I know that... I thought you meant something in the first part, which is the bit I'm focused on for now


OK. If you're stuck on the tany=..., then you need to differentiate using implicit differentiation.

PS: It would help to simplify the RHS by polynomial division first.
(edited 9 years ago)
Reply 8
Original post by ghostwalker
OK. If you're stuck on the tany=..., then you need to differentiate using implicit differentiation.

PS: It would help to simplify the RHS by polynomial division first.

Right ok thank you

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