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Solving Laplace's Equation

Hello, can anyone help solve laplaces equation in plane polar coordinates to be in the form F(r)cos(theta)

Thanks
Reply 1
Original post by jeremy_jackson
Hello, can anyone help solve laplaces equation in plane polar coordinates to be in the form F(r)cos(theta)

Thanks


what exactly would you like to know?
Reply 2
Hey, are you still needing help with this? It's quite an easy problem - I'd be happy to help!


Posted from TSR Mobile
Reply 3
Original post by CosmicJay
Hey, are you still needing help with this? It's quite an easy problem - I'd be happy to help!


Posted from TSR Mobile


easy?

I guess anything is easy if you know how ...
Reply 4
Original post by TeeEm
easy?

I guess anything is easy if you know how ...


If you know the right ansatz your laughing 😉


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Reply 5
Original post by CosmicJay
If you know the right ansatz your laughing 😉


Posted from TSR Mobile


:banana:
Original post by CosmicJay
Hey, are you still needing help with this? It's quite an easy problem - I'd be happy to help!

Posted from TSR Mobile


hello,

yes i am thanks!

not sure what to write for it to just be in the form f(r)costheta rather than having a sine term as well

thank you
Reply 7
Original post by jeremy_jackson
Hello, can anyone help solve laplaces equation in plane polar coordinates to be in the form F(r)cos(theta)

Thanks


post a photo of your question
Reply 8
Original post by jeremy_jackson
hello,

yes i am thanks!

not sure what to write for it to just be in the form f(r)costheta rather than having a sine term as well

thank you


Hey, it sounds like you know what your doing. I'm assuming you've arrived at a general solution including both sine and cosine? If this is the case then you need to apply boundary conditions - these conditions should lead to your f(r)cos theta solution.


Posted from TSR Mobile
Original post by CosmicJay
Hey, it sounds like you know what your doing. I'm assuming you've arrived at a general solution including both sine and cosine? If this is the case then you need to apply boundary conditions - these conditions should lead to your f(r)cos theta solution.


Posted from TSR Mobile


where do i get these boundary conditions from?
This is where I have to echo what TeeEm has said. In the specific question your tackling either boundary conditions should be explicitly given or something in the wording of the question should indicate what the boundary conditions are. They usually come in the form of: when theta = 0...


Posted from TSR Mobile
Laplace's equation is ∇^2φ = 0, in plane polar coordinates. Find its generalsolution of the form φ(r, θ) = f(r) cos θ and show thatφ(r, θ) =  (Ar +Br^-1) cos θ where A and B are arbitrary constants.
Original post by CosmicJay
This is where I have to echo what TeeEm has said. In the specific question your tackling either boundary conditions should be explicitly given or something in the wording of the question should indicate what the boundary conditions are. They usually come in the form of: when theta = 0...


Posted from TSR Mobile


Laplace's equation is ∇^2φ = 0, in plane polar coordinates. Find its generalsolution of the form φ(r, θ) = f(r) cos θ and show thatφ(r, θ) = (Ar +Br^-1) cos θ where A and B are arbitrary constants
Reply 13
Original post by jeremy_jackson
Laplace's equation is ∇^2φ = 0, in plane polar coordinates. Find its generalsolution of the form φ(r, θ) = f(r) cos θ and show thatφ(r, θ) = (Ar +Br^-1) cos θ where A and B are arbitrary constants


will try to help you tonight when I finish work
Original post by jeremy_jackson
Laplace's equation is ∇^2φ = 0, in plane polar coordinates. Find its generalsolution of the form φ(r, θ) = f(r) cos θ and show thatφ(r, θ) = (Ar +Br^-1) cos θ where A and B are arbitrary constants


1. Write the Laplacian in plane polar coords
2. Assume a separable solution of the form ϕ(r,θ)=R(r)T(θ)\phi(r,\theta) = R(r)T(\theta)
3. Substitute this into 1) and write the result in the form P(r)=Q(θ)P(r)=Q(\theta)
4. Deduce something important about P(r),Q(θ)P(r), Q(\theta). (Hint: how can a function of rr be identically equal to a function of θ\theta?)
5. Solve a couple of DEs in r,θr,\theta separately
Reply 15
Original post by jeremy_jackson
Laplace's equation is ∇^2φ = 0, in plane polar coordinates. Find its generalsolution of the form φ(r, θ) = f(r) cos θ and show thatφ(r, θ) = (Ar +Br^-1) cos θ where A and B are arbitrary constants


It looks that atsruser has given some structure to the problem.
If you need more detail quote me.

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