C2 - Rearranging trig identities questions
I understand the identites themselves:
sin^2x = (1-cos^2x)
tanx=(sinx/cosx)
BUT WHY IS REARANGING IT ALL SO HARD?
How can I make it easier?
CASE IN POINT:
How do you rearrange this:
(tanx+1)(sin^2x=3cos^2x)=0
to an equation with just tan?
sin^2x = (1-cos^2x)
tanx=(sinx/cosx)
BUT WHY IS REARANGING IT ALL SO HARD?
How can I make it easier?
CASE IN POINT:
How do you rearrange this:
(tanx+1)(sin^2x=3cos^2x)=0
to an equation with just tan?
(edited 8 years ago)
Original post by brokenlevel23
I understand the identites themselves:
sin^2x = (1-cos^2x)
tanx=(sinx/cosx)
BUT WHY IS REARANGING IT ALL SO HARD?
How can I make it easier?
CASE IN POINT:
How do you rearrange this:
(tanx+1)(sin^2x=3cos^2x)=0
to an equation with just tan?
sin^2x = (1-cos^2x)
tanx=(sinx/cosx)
BUT WHY IS REARANGING IT ALL SO HARD?
How can I make it easier?
CASE IN POINT:
How do you rearrange this:
(tanx+1)(sin^2x=3cos^2x)=0
to an equation with just tan?
tbh you don't need to do that. Because multiplied brackets=0 means solve for each bracket=0.
Original post by brokenlevel23
I understand the identites themselves:
sin^2x = (1-cos^2x)
tanx=(sinx/cosx)
BUT WHY IS REARANGING IT ALL SO HARD?
How can I make it easier?
CASE IN POINT:
How do you rearrange this:
(tanx+1)(sin^2x=3cos^2x)=0
to an equation with just tan?
sin^2x = (1-cos^2x)
tanx=(sinx/cosx)
BUT WHY IS REARANGING IT ALL SO HARD?
How can I make it easier?
CASE IN POINT:
How do you rearrange this:
(tanx+1)(sin^2x=3cos^2x)=0
to an equation with just tan?
But also you could divide by cos^2 x if you're so keen on making the equation a "tan" only one, btw I'm assuming that that equal sign (in bold) is a plus sign.
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