The Student Room Group

C3 Identities question

I can do part a but I was wondering if there's a method I can use to approach part b because I could be here forever thinking of a value of x and y that give me 52.5 and give me the exact values I need..

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Well, I guess it be be re-written as tan(45+7.5)

7.5 is half of 15 which is half of 30

then use addition formulae i guess?

EDIT: it says hence so it wants you to use the thing that you proved in a)
Original post by creativebuzz
I can do part a but I was wondering if there's a method I can use to approach part b because I could be here forever thinking of a value of x and y that give me 52.5 and give me the exact values I need..

Untitled.png


y=52.5x y=52.5-x and also 105=60+45 105=60+45
(edited 8 years ago)
Original post by Dancatpro
Well, I guess it be be re-written as tan(45+7.5)

7.5 is half of 15 which is half of 30

then use addition formulae i guess?

EDIT: it says hence so it wants you to use the thing that you proved in a)


Yeah I understand the whole hence part, but what made you pick 45 and 7.5 and not any other numbers which make 52.5?
Original post by Renzhi10122
y=52.5x y=52.5-x and also 105=60+45 105=60+45



Can you elaborate that abit? I'm not quite sure what you're doing...
Original post by creativebuzz
Yeah I understand the whole hence part, but what made you pick 45 and 7.5 and not any other numbers which make 52.5?


Because you can make those numbers easily using special triangles
Original post by creativebuzz
Can you elaborate that abit? I'm not quite sure what you're doing...


Use part a and set y=52.5x y=52.5-x and then you'll have to use your addition formulae to find cos105 and sin105 and expand.
Original post by Dancatpro
Because you can make those numbers easily using special triangles


So you're trying to say that the method behind it is to opt for the numbers made in special triangles?
Original post by creativebuzz
So you're trying to say that the method behind it is to opt for the numbers made in special triangles?


I might be completely wrong :/
Original post by Dancatpro
I might be completely wrong :/


x = 22.5
y = 30

then solve using 2x=45 and 2y=60
(edited 8 years ago)
Original post by broconomist
x = 7.5
y = 45

then solve using 2x=30 and 2y=90


Btw, 7.5*2=15
Personally, i think the easiest way to do is to just let x=0
Original post by Renzhi10122
Btw, 7.5*2=15


haha oh dear, my bad!
Original post by creativebuzz
So you're trying to say that the method behind it is to opt for the numbers made in special triangles?

If you learn what 30 degrees in and what 45 degrees is for each of the trig functions, then it coms in really helpful, and you may get asked to find an angle such as this with out using a calculator in some papers, so therefore it's good to know the method!

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