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Differentiating logarithms and exponentials homework

Hey,
I am trying to do some differentiating questions but I always get stuck in the last step !! Could someone plz help me.

Questions:
3) f(x)= (1+x^2)e^3x find f'(x) I used the chain and the product rule.

4) y=e^x^2lnx, find dy/fix same methods as before

Thank you image.jpg
Original post by yoomi
Hey,
I am trying to do some differentiating questions but I always get stuck in the last step !! Could someone plz help me.

Questions:
3) f(x)= (1+x^2)e^3x find f'(x) I used the chain and the product rule.

4) y=e^x^2lnx, find dy/fix same methods as before

Thank you image.jpg


For 1) take a common factor out and tidy it up (simplify).

Posted from TSR Mobile
Original post by yoomi
Hey,
I am trying to do some differentiating questions but I always get stuck in the last step !! Could someone plz help me.

Questions:
3) f(x)= (1+x^2)e^3x find f'(x) I used the chain and the product rule.

4) y=e^x^2lnx, find dy/fix same methods as before

Thank you image.jpg


For 2) are you sure it's e2xe^{2x}? Shouldn't it be
Unparseable latex formula:

e^x^2



If so, same as above, common factor out and tidy up.

Posted from TSR Mobile
Reply 3
Original post by Princepieman
For 1) take a common factor out and tidy it up (simplify).

Posted from TSR Mobile


Hmm tha common factor is e^3x right?
So the answer should be e^3x [ 2x +3 (1+x^2) is that right?
Reply 4
Original post by Princepieman
For 2) are you sure it's e2xe^{2x}? Shouldn't it be
Unparseable latex formula:

e^x^2



If so, same as above, common factor out and tidy up.

Posted from TSR Mobile


Yeah sure it's the differentiating of e^x^2
Original post by yoomi
Hmm tha common factor is e^3x right?
So the answer should be e^3x [ 2x +3 (1+x^2) is that right?


Yeah, that's right! Don't forgwt the close bracket though ']'

Original post by yoomi
Yeah sure it's the differentiating of e^x^2


Yeah, so you should have the differentiated original function × the differentiated other function so e^x^2 stays the same.
Reply 6
Original post by Princepieman
Yeah, that's right! Don't forgwt the close bracket though ']'

Thank u I got it now 😁


Yeah, so you should have the differentiated original function × the differentiated other function so e^x^2 stays the same.


My bad I just realised where I got wrong, it should be x^2 as u said. so now I can take out e^x2 as a factor 😁

Thank u so much

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