My whole class, including me, had our confidence crushed after those papers :'(
I am just wondering if you have done the paper in which it said a student suggests that the circuit shown in Figure 6...
It then says discuss the limitations of this circuit when used to collect the data for the characteristic... the mark scheme says its because you cant obtain the full range of pd... I don't get why? Is it because that when you set the resistance of the variable resistor to a maximum there will still be a current drawn through the circuit and so there will be a current through the bulb leading to a pd across it? and you cant get maximum pd across the bulb because there will always be a voltage drop across the variable resistor? I dont get if there is something to do with the fact that the power supply has some internal resistance though? Because that will mean that you cant get full pd across either of them?
I know the potentiometer way is better but do not fully get it, really appreciate if you could help
I am just wondering if you have done the paper in which it said a student suggests that the circuit shown in Figure 6...
It then says discuss the limitations of this circuit when used to collect the data for the characteristic... the mark scheme says its because you cant obtain the full range of pd... I don't get why? Is it because that when you set the resistance of the variable resistor to a maximum there will still be a current drawn through the circuit and so there will be a current through the bulb leading to a pd across it? and you cant get maximum pd across the bulb because there will always be a voltage drop across the variable resistor? I dont get if there is something to do with the fact that the power supply has some internal resistance though? Because that will mean that you cant get full pd across either of them?
I know the potentiometer way is better but do not fully get it, really appreciate if you could help
I think it was because of the internal resistance, voltage is used there so the bulb cannot get the full p.d of the battery? This is from the top of my head, I think that's what I wrote down and got at least 1 of the marks.
Yea, i was thinking along those lines too. The value of the resistor was very similar to the EMF and so I'd assume that any small changes to the resistor wouldn't create much of an effect as a large pd is dropped across the battery anyway
I think it was because of the internal resistance, voltage is used there so the bulb cannot get the full p.d of the battery? This is from the top of my head, I think that's what I wrote down and got at least 1 of the marks.
Probably just read through my practical book as well as read the methods given in the text book for all 6 practicals. During the holidays though seeing as Paper 1 shouldn't have much of that.
Could anyone tell me what each paper covers? I know all units are tested on each paper, but what is the difference between the two papers?
I asked my physics teachers but they didn't really know...
Paper 1 tests all the content, all 6 chapters in the textbook.
Paper 2 also tests that in section B, which is similar to paper 1 questions and section C, which is 30 multiple choice questions. Section A in this paper has the practical skills stuff, like data analysis and uncertainties.
If it all goes badly, we can all cry together here on the forum
Ready for that😂 . To be honest I'm more worried about paper two because of the questions that are making up for the ISA. Because I'm just SHOCKING at those sort of things when it isn't my own data. Let's hope some nice electricity and mechanics stuff comes up
Ready for that😂 . To be honest I'm more worried about paper two because of the questions that are making up for the ISA. Because I'm just SHOCKING at those sort of things when it isn't my own data. Let's hope some nice electricity and mechanics stuff comes up
My worst part is the multiple choice, they are worth 1 mark but amount of working required to get the answer would be worth 3 or 4 marks in Paper 1. The new spec is ridiculous D:
My worst part is the multiple choice, they are worth 1 mark but amount of working required to get the answer would be worth 3 or 4 marks in Paper 1. The new spec is ridiculous D:
True, the working out is enough for an entire 5/6 mark question in some cases💔
Ready for that😂 . To be honest I'm more worried about paper two because of the questions that are making up for the ISA. Because I'm just SHOCKING at those sort of things when it isn't my own data. Let's hope some nice electricity and mechanics stuff comes up
"Nice electricity" haha is this possible 😂 I cant do electricity for my life 😔
I am just wondering if you have done the paper in which it said a student suggests that the circuit shown in Figure 6...
It then says discuss the limitations of this circuit when used to collect the data for the characteristic... the mark scheme says its because you cant obtain the full range of pd... I don't get why? Is it because that when you set the resistance of the variable resistor to a maximum there will still be a current drawn through the circuit and so there will be a current through the bulb leading to a pd across it? and you cant get maximum pd across the bulb because there will always be a voltage drop across the variable resistor? I dont get if there is something to do with the fact that the power supply has some internal resistance though? Because that will mean that you cant get full pd across either of them?
I know the potentiometer way is better but do not fully get it, really appreciate if you could help
Is it possible for you to give me a link to that paper, pleaseee.