Why not just calculate the molarity of the KOH solution after the addition. The pH after this addition is 11.60 and as pH + pOH = 14
Then pOH = 2.4
Therefore the OH- ion concentration = 10^-2.4
This is also the concentration of the KOH
Now you know the volume of solution = 755cm3 and the molarity of the KOH so you can work out the number of moles.
Now work out the no of moles of HCl at the beginning = 0.755 x 0.012
As KOH + HCl --> products (i.e. a 1:1 reaction) then KOH needed to neutralise this number of moles of HCl is the same
Therefore total no of moles of KOH added = (0.755 x 10^-2.4) + (0.755 x 0.012)
And from the moles you can work out the mass...