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Integration

Can I use reverse chain rule to integrate an expression like x(2x+5)^1/2?
Original post by Reisei
Can I use reverse chain rule to integrate an expression like x(2x+5)^1/2?


No. You can use it to integrate (2x+5)1/2(2x+5)^{1/2} though
Reply 2
Ok thank you, is there a rule for which expressions you can integrate using reverse chain rule?
Original post by Reisei
Ok thank you, is there a rule for which expressions you can integrate using reverse chain rule?

any expression with a power
Original post by assassinbunny123
any expression with a power


Er... so we discarding sin(2x+1)\sin(2x+1) now?

Original post by Reisei
Ok thank you, is there a rule for which expressions you can integrate using reverse chain rule?


'Reverse chain rule' is essentially substitution. You can use it whenever you're integrating an expression of the form g(x)fg(x)g'(x) \cdot fg(x). where fg(x)fg(x) means f(g(x))f(g(x)) so that gg is inside ff.

I.e. 2xsin(x2+5)2x\sin(x^2+5) or (3x22x+1)ex3x2+x(3x^2-2x+1)e^{x^3-x^2+x}

But I think the term itself is often used at A-Level when g(x)g(x) is a linear function so that g(x)g'(x) is a constant so it doesn't really matter.

These ones are simpler and have the form (ax+b)α(ax+b)^{\alpha}
(edited 5 years ago)
Original post by assassinbunny123
any expression with a power


if you're talking about such as e2x e^{2x} then yes.

With the example you gave earlier, what you'll need is integration by parts.

Remember that during reverse chain rule, if you end up multiplying the expression with something that has the variable in it (x, or the one you're using), then you're using the wrong method.
(edited 5 years ago)
Original post by DunkenDonuts

what you'll need is product rule.


For integration...?
Just complexify the integral ;-)
Original post by RDKGames
For integration...?


Oops, not differentiation. Sorry.

I'll edit the post. :smile:
Original post by RDKGames
For integration...?


reverse product rule, ie integrating by parts

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