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Trig

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ii) I am confused on how to do it.
Original post by znx
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ii) I am confused on how to do it.


arcsin is the same as cos1 \cos^{1} (which I'm pretty sure you know)

Use that information.

For part a, add π \pi to both sides and divide by 6 to get arcsin on it's own, and use the information I gave you.

For part b, approach it using simply trigonometric identities.
Original post by znx

ii) I am confused on how to do it.


Have you considered arcsinx\arcsin x that can be rewritten in terms of arccosx\arccos x ?
(edited 5 years ago)
Reply 3
Original post by RDKGames
Have you considered arcsinx\arcsin x that can be rewritten in terms of arccos\arccos with a slightly different argument?


y = arccos x
arcsin x = y?
Original post by znx
y = arccos x
arcsin x = y?


arccosxπ2arcsinx\arccos x \equiv \frac{\pi}{2} - \arcsin x
Reply 5
Thank you :smile:
Original post by RDKGames
arccosxπ2arcsinx\arccos x \equiv \frac{\pi}{2} - \arcsin x

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