The equation dG=, on the defonition part. what does the d represent cus thought it was delta but isn't due to y dont they use the delta symbol ( which they do do later on ) sorry for uch a silly ? cheers for any help
Errr, no, ΔG=dG. The function 'dG' is the differential of G. See here if you don't know what that is. So the fundamental equation for Gibbs energy is dG=Vdp-SdT (as can easily be shown from first principles), and one of the good things about writing it like this is that you know instantly, since Gibbs energy is a state function (and which therefore behaves 'nicely' - i.e. you can write the total derivative), that ∂p∂GT=V and so on.
ΔG on the other hand represents a change in Gibbs energy from some place to another, usually the Gibbs energy change of a reaction or phase transition and so forth.
(Also, for reference, ∂G/∂p is the partial derivative of G with respect to p.)
Another little thing is that dG is not some measurable quantity. The various master equations don't allow you to plug in numbers and work out values for things. They dictate the relationships between different quantities as Sinuhe has explained above.