Stuck on a chemistry question.
The question says: A student plans a method to prepare pure crystals of copper sulfate the students method is:
1. Add one spatula of calcium carbonate to dilute the hydrochloric acid in a beaker.
2. When the fizzing stops, heat the solution with a Bunsen burner until all the liquid is gone.
The method contains several errors and does not produce copper sulfate crystals.
Explain the improvements the student should make to the method so that pure crystals of copper sulfate are produced.
1. Add one spatula of calcium carbonate to dilute the hydrochloric acid in a beaker.
2. When the fizzing stops, heat the solution with a Bunsen burner until all the liquid is gone.
The method contains several errors and does not produce copper sulfate crystals.
Explain the improvements the student should make to the method so that pure crystals of copper sulfate are produced.
Original post by ardz
The question says: A student plans a method to prepare pure crystals of copper sulfate the students method is:
1. Add one spatula of calcium carbonate to dilute the hydrochloric acid in a beaker.
2. When the fizzing stops, heat the solution with a Bunsen burner until all the liquid is gone.
The method contains several errors and does not produce copper sulfate crystals.
Explain the improvements the student should make to the method so that pure crystals of copper sulfate are produced.
1. Add one spatula of calcium carbonate to dilute the hydrochloric acid in a beaker.
2. When the fizzing stops, heat the solution with a Bunsen burner until all the liquid is gone.
The method contains several errors and does not produce copper sulfate crystals.
Explain the improvements the student should make to the method so that pure crystals of copper sulfate are produced.
The student actually made calcium oxide and carbon dioxide!!??? .He shoild have been sent home! lol.Start with copper oxide to excess and sulphuric acid in a flask in a warm water bath. Stir it. Filter it. Throw the filter paper away. Warm up the solution and let half of it evaporate. Then pour the remaining solution into a evaporating dish. Leave it to to dry out! You now have copper sulphate crystals. Easy!
Original post by ardz
The question says: A student plans a method to prepare pure crystals of copper sulfate the students method is:
1. Add one spatula of calcium carbonate to dilute the hydrochloric acid in a beaker.
2. When the fizzing stops, heat the solution with a Bunsen burner until all the liquid is gone.
The method contains several errors and does not produce copper sulfate crystals.
Explain the improvements the student should make to the method so that pure crystals of copper sulfate are produced.
1. Add one spatula of calcium carbonate to dilute the hydrochloric acid in a beaker.
2. When the fizzing stops, heat the solution with a Bunsen burner until all the liquid is gone.
The method contains several errors and does not produce copper sulfate crystals.
Explain the improvements the student should make to the method so that pure crystals of copper sulfate are produced.
wasreallyhelpfull
Original post by kai knight
wasreallyhelpfull
good. no problem!
So would you pour copper oxide into the sulphuric acid (in the flask) and leave it in a warm water bath. Then stir, filter it afterwards?
Original post by sleezyshrimp
So would you pour copper oxide into the sulphuric acid (in the flask) and leave it in a warm water bath. Then stir, filter it afterwards?
You need an excess of the CuO.
You need to evaporate off the water from the filtrate.
If you need dry crystals, you will need to put them in a warm oven.
Original post by sleezyshrimp
So would you pour copper oxide into the sulphuric acid (in the flask) and leave it in a warm water bath. Then stir, filter it afterwards?
Copper oxide first, then add the sulphuric acid. Stir. Leave it for 10 mins. then filter it!
Original post by mgi
Copper oxide first, then add the sulphuric acid. Stir. Leave it for 10 mins. then filter it!
It doesn't matter which you add to which.
Original post by Pigster
It doesn't matter which you add to which.
no. its just a preference.
Original post by mgi
no. its just a preference.
My preference is to start with the acid and add the solid. If it all reacts, add some more, etc. until some solid remains. That way, I don't have to be bothered to do the calculation or get out a balance to ensure the base is in excess.
Original post by Pigster
My preference is to start with the acid and add the solid. If it all reacts, add some more, etc. until some solid remains. That way, I don't have to be bothered to do the calculation or get out a balance to ensure the base is in excess.
No its not my preference. Do the excess calculation in the planning , weigh out the required amount of solid and measure out the volume of acid. Simple. No guesswork or seeing if it reacts! it will react, we already know that!
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