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M1 January 2005 discussion thread.
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Any help would be greatly appreciated
Widowmaker
I did a bit of decision/statistics last year and I found it harder than pure and mechanics.
Horses for courses, guys.
I did Edexcel Decision1 last year and got 100%...
...However, I ought to add that I have 30+ years experience of timetabling, scheduling, programming, etc... so not to sit it would have been a waste.
Take what you're good at. Get the points.
Aitch
Any more revision questions?
nas7232
how do you do all parts of reptiles question?
I can only ever be able to find out what r and s is and that's it for me, rest of the vector question i can't do.
I can only ever be able to find out what r and s is and that's it for me, rest of the vector question i can't do.
reptiles?
Two forces F1 and F2 act on a particle. The force F1 is parallel to the vector (i+j) and the force F2 is parallel to the vector (i+2j). Given that the resultant R of these two forces is of magnitude 15N and parallel to the vector (3i+4j), find the magnitude of F1 and the magnitude of F2.
What answer do you get?
What answer do you get?
If a force is parallel to a vector let us say b then it means that the direction in which it is acting is kb, where k is an arbitary constant.
"Given that the resultant R of these two forces is of magnitude 15N and parallel to the vector (3i+4j)"
That means that the direction in which the force is acting is k(3i+4j).
=>|F|=15=root(k^2)root((3^2)+(4^2))=kroot25=5k
=> 15=5k
=> k=3
That means that F1 is in the vector direction of (3i+3j). Therefore:
|F1|=root((3^2)+(3^2))=root(9+9)=root(9(1+1))=root(9)root2=3root(2)
Consequently F2 is in the direction of (3i+6j). Therefore:
|F2|=root((3^2)+(6^2))=root(9+36)=root(9(1+4))=root(9)root(5)=3root(5)
Newton.
"Given that the resultant R of these two forces is of magnitude 15N and parallel to the vector (3i+4j)"
That means that the direction in which the force is acting is k(3i+4j).
=>|F|=15=root(k^2)root((3^2)+(4^2))=kroot25=5k
=> 15=5k
=> k=3
That means that F1 is in the vector direction of (3i+3j). Therefore:
|F1|=root((3^2)+(3^2))=root(9+9)=root(9(1+1))=root(9)root2=3root(2)
Consequently F2 is in the direction of (3i+6j). Therefore:
|F2|=root((3^2)+(6^2))=root(9+36)=root(9(1+4))=root(9)root(5)=3root(5)
Newton.
Kuddly!
IM soo crap at moments!! i understand and can do every past paper questions except the moments ones!!!
any tips on how to revise on that? or understand that
any tips on how to revise on that? or understand that
If a beam/rod is about to tilt on one of its pivots the reaction at the other pivots goes to zero.
Resolve forces upwards and downwards, or take moments about a point where there is an unknown e.g. a reaction R. If there are 2 unknowns, e.g. reaction and weight and you have to find weight, take moments about the point where the unknown reaction is.
In equilibirum, forces add up to zero.
Remember mathematical models assumed in this chapter.
uniform rod - c.o.m at centre so weight acts at centre.
non-uniform rod - centre of mass not at centre and so position of weight might have to be found.
rod - length is only considered here, all other dimensions (e.g. width) are ignored.
Always draw diagrams no matter how simple the question might seem.
That's all the advice I can give.
Go through all the moments exam questions in heinemann book and exam papers and you will get there.
Are you taking in Jan?
thanx a lot hun!
but you see i know all the information about moments
but when it comes to resolving them, i dont know which way the moment at the pivots/centre of mass go? like anticlockwise or clockwise, and what distance to multiply it!
i can do the easy questions but the hard ones are a killer
yes im taking it next monday
! i toook it in june 2!...got a B but messed up in the moment question...
but you see i know all the information about moments
but when it comes to resolving them, i dont know which way the moment at the pivots/centre of mass go? like anticlockwise or clockwise, and what distance to multiply it!
i can do the easy questions but the hard ones are a killer
yes im taking it next monday
! i toook it in june 2!...got a B but messed up in the moment question...Kuddly!
thanx a lot hun!
but you see i know all the information about moments
but when it comes to resolving them, i dont know which way the moment at the pivots/centre of mass go? like anticlockwise or clockwise, and what distance to multiply it!
i can do the easy questions but the hard ones are a killer
yes im taking it next monday! i toook it in june 2!...got a B but messed up in the moment question...
but you see i know all the information about moments
but when it comes to resolving them, i dont know which way the moment at the pivots/centre of mass go? like anticlockwise or clockwise, and what distance to multiply it!
i can do the easy questions but the hard ones are a killer
yes im taking it next monday
! i toook it in june 2!...got a B but messed up in the moment question...It's next wednesday isn't it?
Kuddly!
thanx a lot hun!
but you see i know all the information about moments
but when it comes to resolving them, i dont know which way the moment at the pivots/centre of mass go? like anticlockwise or clockwise, and what distance to multiply it!
i can do the easy questions but the hard ones are a killer
yes im taking it next monday! i toook it in june 2!...got a B but messed up in the moment question...
but you see i know all the information about moments
but when it comes to resolving them, i dont know which way the moment at the pivots/centre of mass go? like anticlockwise or clockwise, and what distance to multiply it!
i can do the easy questions but the hard ones are a killer
yes im taking it next monday
! i toook it in june 2!...got a B but messed up in the moment question...Do you mean moments in vector form?
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