The Student Room Group

Scroll to see replies

Reply 40
(x1)[2(2x+1)2]+(2x+1)1(x-1)[-2(2x+1)^{-2}]+(2x+1)^{-1}
(2x+2)(2x+1)2+(2x+1)1(-2x+2)(2x+1)^{-2}+(2x+1)^{-1}
(2x+2)(2x+1)2+1(2x+1)\frac{(-2x+2)}{(2x+1)^2}+\frac{1}{(2x+1)}
(2x+2)(2x+1)(2x+1)+(2x+1)(2x+1)(2x+1)\frac{(-2x+2)}{(2x+1)(2x+1)}+\frac{(2x+1)}{(2x+1)(2x+1)}
(2x+2)+(2x+1)(2x+1)2\frac{(-2x+2)+(2x+1)}{(2x+1)^2}
3(2x+1)2\frac{3}{(2x+1)^2}
D-Day
(x1)[2(2x+1)2]+(2x+1)1(x-1)[-2(2x+1)^{-2}]+(2x+1)^{-1}
(2x+2)(2x+1)2+(2x+1)1(-2x+2)(2x+1)^{-2}+(2x+1)^{-1}
(2x+2)(2x+1)2+1(2x+1)\frac{(-2x+2)}{(2x+1)^2}+\frac{1}{(2x+1)}
(2x+2)(2x+1)(2x+1)+(2x+1)(2x+1)(2x+1)\frac{(-2x+2)}{(2x+1)(2x+1)}+\frac{(2x+1)}{(2x+1)(2x+1)}
(2x+2)+(2x+1)(2x+1)2\frac{(-2x+2)+(2x+1)}{(2x+1)^2}
3(2x+1)2\frac{3}{(2x+1)^2}


OMG! where did that fraction come from? you have offically scared me! :eek: i think i'm gonna skip that question......:s-smilie:
Reply 42
A negative exponent moves whatever is raised to that negative exponent to the bottom of a fraction.
D-Day
A negative exponent moves whatever is raised to that negative exponent to the bottom of a fraction.


Argh..i',m gonna start crying in a minute... :confused:

Latest