The Student Room Group

Line integrals in polar coordinates

Given the thorem:
If
Unparseable latex formula:

$$ z = x+iy, f(z)=u(x,y)+iv(x,y) $$



Then

Unparseable latex formula:

$$ \int_\gamma f(z) dz = \int_\gamma {(u dx - v dy)} + i \int_\gamma {(u dy + v dx) } $$



How do modify this theorem for z=reiθ z = re^{i\theta} ?

is it simply:

f(z)=u(r,θ)+iv(r,θ) f(z)=u(r,\theta)+iv(r,\theta)

Unparseable latex formula:

$$ \int_\gamma f(z) dz = \int_\gamma {(u dr - vr d\theta)} + i \int_\gamma {(ur d\theta + v dr) } $$

?

Thanks,
jb444
Reply 1
Th theorem works because dz=zxdx+zydy=dx+idy dz = \frac{\partial z}{\partial x} dx + \frac{\partial z}{\partial y}dy = dx + idy by the chain rule.

The expression for dz in terms of r and theta is dz=zrdr+zθdθdz = \frac{\partial z}{\partial r} dr + \frac{\partial z}{\partial \theta}d\theta .

I'll leave you to work out how this affects the integrands.

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