ok thanks
(Original post by Skiwi)Exact workings aren't allowed on the forum but use what below and you should be able to.get there
If you have a value in front of a log then you can bring it into to it. So alogx is logx^a.
Log(a)+log(b) =log(ab)
Log(a)-log(b)=log(a/b)
thanks for help
(Original post by Skiwi)Exact workings aren't allowed on the forum but use what below and you should be able to.get there
If you have a value in front of a log then you can bring it into to it. So alogx is logx^a.
Log(a)+log(b) =log(ab)
Log(a)-log(b)=log(a/b)
thanks for help
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