Original post by vegan1974
does anyone know how to work out the following
-3e^7a+9 + 6 = -6
2^2x-1 = 4^3
Thanks
-3e^7a+9 + 6 = -6
2^2x-1 = 4^3
Thanks
For the first one, assuming you mean -3e^(7a+9) + 6 = -6, then get the exponential term on one side, the numbers on the other side, then take natural logs.
For the second one, assuming you mean 2^(2x-1) = 4^3, then note that 4 = 2^2, then go from there.
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