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Diffrentiation and tangent question C3

y=xe2x y= xe^2x

find the equation of the tangent to the above curve at the point (0.5,0.5e)

for the simplicitry of this, say i worked out dy/dx = 2

then do we use [latex]y-y1= m(x-x1)?

getting: y0.5e=2(x0.5)y - 0.5e = 2(x - 0.5)
y=2x+1+0.5e y = 2x+1+ 0.5e

where do i go from here? what do i do with the e?

thanks
Reply 1
That's it. You're done.
the curve is meant to be xe to the power of 2x, how do i put this in latex?
the anwer says: y=2exe/2y = 2ex - e/2

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