Original post by Dell PC 2
Idk what's going on in this
.
what exam board is this
Original post by danhas20
what exam board is this
ccea for as chemistry
it was in their 2019 paper as2
Original post by Dell PC 2
ccea for as chemistry
it was in their 2019 paper as2
it was in their 2019 paper as2
no idea sorry man, i do ocr
Original post by danhas20
what exam board is this
If you remove the bromine atom (and, of course, one hydrogen), there are three possible positions in which a C=C bond could form:
-Between the central carbon in the CH(CH3)2 group and the carbon in the C-Br.
-Between the carbon in the CH3 and the carbon in the C-Br.
-Between the carbon in the CH2 and the C-Br.
Try drawing the structures of each of these three possible alkenes. Any where there are 2 different groups on each carbon in the C=C bond will form a pair of E/Z isomers.
Edit: oops responded to the wrong post, meant to quote the original. Wow I’m tired lol.
(edited 11 months ago)
Original post by danhas20
no idea sorry man, i do ocr
Just a heads up, this type of question does assess content that comes up in the specifications for all the major UK exam boards- including OCR A and B. You may be asked something similar in your actual exams.
Original post by TypicalNerd
If you remove the bromine atom (and, of course, one hydrogen), there are three possible positions in which a C=C bond could form:
-Between the central carbon in the CH(CH3)2 group and the carbon in the C-Br.
-Between the carbon in the CH3 and the carbon in the C-Br.
-Between the carbon in the CH2 and the C-Br.
Try drawing the structures of each of these three possible alkenes. Any where there are 2 different groups on each carbon in the C=C bond will form a pair of E/Z isomers.
Edit: oops responded to the wrong post, meant to quote the original. Wow I’m tired lol.
-Between the central carbon in the CH(CH3)2 group and the carbon in the C-Br.
-Between the carbon in the CH3 and the carbon in the C-Br.
-Between the carbon in the CH2 and the C-Br.
Try drawing the structures of each of these three possible alkenes. Any where there are 2 different groups on each carbon in the C=C bond will form a pair of E/Z isomers.
Edit: oops responded to the wrong post, meant to quote the original. Wow I’m tired lol.
Is this what the molecules are supposed to look like?
Also, how am I supposed to get the correct answer in under a minute?
Original post by Dell PC 2
Is this what the molecules are supposed to look like?
Also, how am I supposed to get the correct answer in under a minute?
Is this what the molecules are supposed to look like?
Also, how am I supposed to get the correct answer in under a minute?
If the bromoalkane you copied down was correct, you would have drawn the correct alkenes- but you missed one carbon on the molecule and that does affect the answer.
Yeah, you need longer than a minute to answer that question imo.
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