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AQA A level further maths paper 3 - statistics question

Hi everyone I'd be so grateful if someone can answer this.
So I'm sitting paper 3 tomorrow and there's one thing I'm a little fuzzy on and I just can't find any answers by googling.

With the exponential distribution, there's a way to find F(x) first without using f(x). In my textbook it says "P(T<t)=1-P(T>t)=1-P(no occurrences in interval t)=1-e^(-xt)" (x is the parameter and 1/x is the mean). I understand it all except I have no idea how to get p(no occurrences in interval t). I was thinking perhaps it's the formula for Poisson with x=0? But then I don't know why there is now a t there. I've seen a few questions asking to find F(x) so I want to understand this in case it comes up tomorrow. Thank you!
Original post by entitree
Hi everyone I'd be so grateful if someone can answer this.
So I'm sitting paper 3 tomorrow and there's one thing I'm a little fuzzy on and I just can't find any answers by googling.

With the exponential distribution, there's a way to find F(x) first without using f(x). In my textbook it says "P(T<t)=1-P(T>t)=1-P(no occurrences in interval t)=1-e^(-xt)" (x is the parameter and 1/x is the mean). I understand it all except I have no idea how to get p(no occurrences in interval t). I was thinking perhaps it's the formula for Poisson with x=0? But then I don't know why there is now a t there. I've seen a few questions asking to find F(x) so I want to understand this in case it comes up tomorrow. Thank you!

Assuming x is a normalised rate parameter here (mean events per unit time) then the number of events in t periods will have the distribution Po(xt).
Reply 2
Original post by old_engineer
Assuming x is a normalised rate parameter here (mean events per unit time) then the number of events in t periods will have the distribution Po(xt).

Okay that makes sense, thank you very much!

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