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Essential Pre-Uni Physics C4a.4

https://isaacphysics.org/questions/phys19_c4a_q4?board=phys19_c4_add&stage=a_level
Struggling with Part C of the question. The answer to part A is 18/7 R and the answer to part B is 2/9V. I solved B by taking the equivalent resistance of the 7 resistors on the right side of the circuit and then just using the ratios between that equivalent resistor and the 2 R’s left. I tried that for C but I’m not getting the right answer. Any help would be appreciated.
Reply 1
I'd say you already did the heavy lifting for C in part B

the PD across R2 is half the PD across R1 because the PD across R1 is divided across the 2 identical triangular resistor networks on the right of the diagram
Reply 2
Original post by Joinedup
I'd say you already did the heavy lifting for C in part B

the PD across R2 is half the PD across R1 because the PD across R1 is divided across the 2 identical triangular resistor networks on the right of the diagram

Ahh I see. Thank you very much.

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