I am stuck on this question! I have no idea what to do first or how to answer it. Please.
In an MgSO4 solution, a current of 36μA flows. Work out how many SO4^2- ions pass a point in 15s. [Hint: assume that the Mg^2+ ions and SO4^2−ions move at the same speed in opposite directions and the movement of each type of ion is responsible for half the current]
I am stuck on this question! I have no idea what to do first or how to answer it. Please.
In an MgSO4 solution, a current of 36μA flows. Work out how many SO4^2- ions pass a point in 15s. [Hint: assume that the Mg^2+ ions and SO4^2−ions move at the same speed in opposite directions and the movement of each type of ion is responsible for half the current]
Not a normal chemistry question, more of a physics issue. However: 1A is one coulomb of charge per second Hence 36 μA = 3.6 x 10-5 Cs-1 In 15 seconds: Charge passed = 15 x 3.6 x 10-5 C = 5.4 x 10-4 C If half of the charge is per ion then each ion moves 2.7 x 10-4 C There are 96485 coulombs in 1F and this is equivalent to 6.0223 x 1023 electrons Hence 6.0223 x 1023 x 2.7 x 10-4/96485 electrons = 1.69 x 1015 electrons But each ion carries two charges, therefore the total number of each ion passing is 8.43 x 1014
Not a normal chemistry question, more of a physics issue. However: 1A is one coulomb of charge per second Hence 36 μA = 3.6 x 10-5 Cs-1 In 15 seconds: Charge passed = 15 x 3.6 x 10-5 C = 5.4 x 10-4 C If half of the charge is per ion then each ion moves 2.7 x 10-4 C There are 96485 coulombs in 1F and this is equivalent to 6.0223 x 1023 electrons Hence 6.0223 x 1023 x 2.7 x 10-4/96485 electrons = 1.69 x 1015 electrons But each ion carries two charges, therefore the total number of each ion passing is 8.43 x 1014
Yes, I’m sorry I’m new to the student room so I think I submitted it incorrectly.
Thank you so much, this makes much more sense now.