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Barometric Formula Isaac Physics

I have done part a and b, but I am unsure how to integrate to get partc. I am slightly confused about this step and Im not sure if my working is in the right direction?

EDIT Q LINK: https://isaacphysics.org/questions/rmets_barometric_formula?board=9508987c-b632-456f-b748-3783c5ecb32c&stage=a_level
(edited 2 months ago)
Reply 1
My working (for part c)
Original post by mosaurlodon
I have done part a and b, but I am unsure how to integrate to get partc. I am slightly confused about this step and Im not sure if my working is in the right direction?


Original post by mosaurlodon
My working (for part c)


You are in the right direction except…

dPdz=PMgRT \dfrac{dP}{dz} = -\dfrac{PMg}{RT} ---------Eqn(1)

this is right :smile:

However, the next step is wrong. :frown:

Before, you do the integration, move the pressure term P on the right side to the left side while moving dz to the right side in eqn(1).

If you have a problem, watch the following video.
https://youtu.be/H1oKKXn5NsQ?si=qGOG37WjMAom4dy0
Original post by mosaurlodon
I have done part a and b, but I am unsure how to integrate to get partc. I am slightly confused about this step and Im not sure if my working is in the right direction?


I recommend that you post the link to the question in future to save the helper the trouble of searching for the question.
Reply 4
Original post by Eimmanuel
You are in the right direction except…

dPdz=PMgRT \dfrac{dP}{dz} = -\dfrac{PMg}{RT} ---------Eqn(1)

this is right :smile:

However, the next step is wrong. :frown:

Before, you do the integration, move the pressure term P on the right side to the left side while moving dz to the right side in eqn(1).

If you have a problem, watch the following video.
https://youtu.be/H1oKKXn5NsQ?si=qGOG37WjMAom4dy0

Thanks for the video, I have followed the steps and have got this, but it doesn't give me the right answer on isaac, can you tell me whats going wrong here.
(edited 2 months ago)
Reply 5
Original post by Eimmanuel
I recommend that you post the link to the question in future to save the helper the trouble of searching for the question.

Sorry editted the post, and will do from now on.
Reply 6
Original post by mosaurlodon
Thanks for the video, I have followed the steps and have got this, but it doesn't give me the right answer on isaac, can you tell me whats going wrong here.

Here is my working
Original post by mosaurlodon
Here is my working


You are almost correct.

The integral should look like:

P(0)P(z)dPP=0zMgRTdz \int_{P(0)}^{P(z)} \frac{dP'}{P'} = \int_0^z \frac{-Mg}{RT} dz'

I am using dummy variables if you don't understand consult a calculus text.
(edited 2 months ago)
Reply 8
Ah thank you! I've got it now
Reply 9
Original post by mosaurlodon
Ah thank you! I've got it now

wwwww still not find where is the mistake

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