There are "two ways" of attempting the question. In fact, they are essentially the same thing. First way, use the gradient that you have found in part A. At the y-intercept, the point is (0, c), where c is the y-intercept. Hope you know why. Then you can pick another point on the straight line. Use the gradient formula to find c.
The second way is to write the equation of the straight line: y = mx + c, where m is the gradient and c is the y-intercept. Again pick a point from the straight line and sub into the equation y = mx + c to find c.