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Integration by Substitution



I got parts a & b but there's something I want to ask in general but using this as an example. In part c) I have to do dx/du but how do I know when to do that? I'm sure it hasn't come up in all the papers but I tripped up on the question because I got up to :

4/2 (b:a)[x^3(lnu)du] but didn't get past this stage till I went through it with Exam Solutions, can anyone tell me when to look out for it please
Reply 1
You have

x3ln(x2+2) dx \displaystyle \int x^3 \ln (x^2+2) \ dx

and you need to change this to an integral du using the substitution u=x2+2\displaystyle u=x^2+2

The way to change dx to du is to find du/dx:

dudx=2x    dx=du2x \displaystyle \frac{du}{dx} = 2x \implies dx = \frac{du}{2x}

Now substutute everything in, remembering that x2=u2x^2=u-2.

Post your working if you're still stuck. Or post the specific part that confuses you.
Reply 2
You have to do dx/du (or similar) for every substitution. It is how you change the dx into a du.
Reply 3
Thank you both, I got it now :smile:

I was getting confused before because I thought it was an additional step. One question though - when you're finding the area/volume of a curve using Integration and I know when they are parametric, you add a little bit after the integral of y^2 as in it'll dx/dt*dt or something?

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