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Quick Standard Deviation Question

I have sigma x = 1810.8, sigma x^2 = 156460.1 for a sample of 25.

so we can work out the mean by sigma x / 25

how would i work out the standard deviation, thanks :smile:

Reply 1

Chwirkytheappleboy

If you check out Wikipedia you'll find a few variations of the standard deviation formula. I think the one that will be most useful to you is this:

\sigma = \sqrt{\dfrac{1}{N}\left(\displaystyle \sum_{i=1}^Nx^2_i\right)-\bar{x}^2}

Reply 2

username165864

Chwirkytheappleboy

If you check out Wikipedia you'll find a few variations of the standard deviation formula. I think the one that will be most useful to you is this:

\sigma = \sqrt{\dfrac{1}{N}\left(\displaystyle \sum_{i=1}^Nx^2_i\right)-\bar{x}^2}

The formula may vary slightly (the

\frac{1}{N}

becoming

\frac{1}{N-1}

) so as to prevent dividing by 0 (i.e. is valid for a small sample).

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