2 mark Circle questions

For question a you have to create a graph showing how h and the angle work. I think the angle should be placed on the x axis and the h on the y axis. In the graph I reckon it'l start of with an increase followed by a big decrease and then the graph will go back to 0h by an increase.

angle
------ X 2 X pi X h for the second question on amazing maths
360

(edited 12 years ago)

Reply 3

SilentIdea

1

Original post by krisshP

For question a you have to create a graph showing how h and the angle work. I think the angle should be placed on the x axis and the h on the y axis. In the graph I reckon it'l start of with an increase followed by a big decrease and then the graph will go back to 0h by an increase.

angle
------ X 2 X pi X h
360

You can't have a negative h.

Reply 4

Original post by SilentIdea

You can't have a negative h.

But in the second question they are ONLY talking about the picture's circle.

h can be negative, but in the picture it isn't, so assume it's positive.

Check your answer though.

Reply 5

SilentIdea

1

Original post by krisshP

But in the second question they are ONLY talking about the picture's circle.

h can be negative, but in the picture it isn't, so assume it's positive.

Check your answer though.

When drawing the graph, h increases as theta increases up to 180 degrees. After that, h decreases to 0 metres while theta increases to 360 degrees.

Reply 6

F1Addict

12

For b, think trigonometric graphs and their transformations. :smile:

Reply 7

By the way, wouldn't the graph be similar to the sine graph? I think so.

For the last question:
you HAVE to have done the previous question. Look at the graph. Draw a STRAIGHT line from left to right on the graph at which h=100. After making the line, find the angles which intersect the line. These angles should be your answers. As an estimate I reckon there will be only 2 angles as the answers.

Reply 8

Original post by SilentIdea

You can't have a negative h.

Actually, you are right. :wink:

I looked at the question again with a fresh eye.

The graph I now think will increase and then decrease. Sorry. but NEVER will there be a negative h.

(edited 12 years ago)

Reply 9

Original post by blueray

Can someone explain to me how to answer these questions? :smile:

Is this AddMaths!

Reply 10

Above.The.Empyrean

I can do this for you if you would like? It's Additional Maths if I'm correct? I'm in Year 11 as well. There's an easy method to do this, I'll show you my method.

(edited 12 years ago)

Reply 11

Original post by Above.The.Empyrean

I can do this for you if you would like? It's Additional Maths if I'm correct? I'm in Year 11 as well. There's an easy method to do this, I'll show you my method. One second.

This is not additional maths! We have never done anything like this!!!!

Reply 12

TenOfThem

18

Original post by GreenLantern1

This is not additional maths! We have never done anything like this!!!!

I am sure that you have ... it is very straightforward trig

Reply 13

Above.The.Empyrean

*ps - this is part b. It goes from i) - v) to simplify the stages. It's simple trig identities.

This is unequivocally additional maths. I even have the past paper right in front of me with this tantamount question.

(edited 12 years ago)

Reply 14

USB

2

Original post by Above.The.Empyrean

This is unequivocally additional maths. I even have the past paper right in front of me with this tantamount question.

Yeah, its about the relationship between Sin and Cos (in this case Cos) (and can also be used to prove Euler's identity I think :smile:

)

Reply 15

Original post by Above.The.Empyrean

This is unequivocally additional maths. I even have the past paper right in front of me with this tantamount question.

It won't be OCR MEI Additional Maths FSMQ that the OP is doing! I have never seen this in a past paper. Send me the link for the past paper then.

Reply 16