Original post by goodwinning
Can anyone help with this and please explain the reasoning behind the answer?
Can anyone help with this and please explain the reasoning behind the answer?
In the spontaneous reaction E(cell) which is calculated from E(red) - E(ox) mustbe positive.
The half-cell (electrode) that provides electrons is the most negative of the pair (nost easily oxidised, better reducing agent).
With these two pieces of information you should be able to answer the question.
So since current is flowing from B to A would (2) be the anode and (1) the cathode?
Posted from TSR Mobile
Posted from TSR Mobile
Original post by goodwinning
So since current is flowing from B to A would (2) be the anode and (1) the cathode?
Posted from TSR Mobile
Posted from TSR Mobile
Oxidation always happens at the anode.
Quick Reply
Related discussions
- how do u know when to say ions/electrons
- Electrochemistry
- Electrochemistry help
- Chemistry lectures for personal statement
- What is actually studied in a chemistry degree?
- Chem a level - electrochemistry
- Electrochemistry and effect of pressure
- chemistry at uni?
- AQA A Level Chemistry Electrochemistry
- Chemistry at Uni?
- Urgent help with resistance of water
- AS/A Level Chemistry Study Group 2023/2024
- Ask a Chemistry Uni Student!
- reuben's y13/medapps journey!!
- Holding myself accountable; study!
- AQA A Level Chemistry Paper 3 7405/3 - 23 Jun 2022 [Exam Chat]
- AQA A-Level Chemistry Paper 3 (7405/3) - 23rd June 2023 [Exam Chat]
- OCR A Level Chemistry Paper 1 H432/01 - 13th Jun 2022 [Exam Chat]
- The Ultimate Chat Thread!
- University of Oxford 2024 Undergraduate Applicants Official Thread
Latest
Trending
Last reply 1 week ago
Im confused about this chemistry question, why does it form these productsTrending
Last reply 1 week ago
Im confused about this chemistry question, why does it form these products
