When dichromate ions (VI) ions, Cr2O7 2- , react with iron (II) ions in acidic solution, the products are chromium (III) ions and iron (III) ions. In what ratio do the dichromate (VI) ions and the iron (II) ions react?
A 1:6 B 1:5 C 2:5 D 1:3
I initially thought this would be a simple question, maybe I'm missing something? Thanks in advance!
The full ionic equation must not contain electrons. One of the half equations must be multiplied by a number so that when they are combined, the electrons cancel. I.e. same number of electrons in the reactants and products
The full ionic equation must not contain electrons. One of the half equations must be multiplied by a number so that when they are combined, the electrons cancel. I.e. same number of electrons in the reactants and products
OMGGGG how did I miss that???! THANK YOUUUU so much, it's been a long day for me I'm so nervous for this exam as well
When dichromate ions (VI) ions, Cr2O7 2- , react with iron (II) ions in acidic solution, the products are chromium (III) ions and iron (III) ions. In what ratio do the dichromate (VI) ions and the iron (II) ions react?
A 1:6 B 1:5 C 2:5 D 1:3
I initially thought this would be a simple question, maybe I'm missing something? Thanks in advance!
These are the half equations:
Cr2O72- + 14H+ + 6e --> 2Cr3+ + 7H2O
Fe2+ --> Fe3+ + 1e
Now can you see the ratio in which they have to react?