Using corrected value for hardy cross method

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Spreadsheet attached. Ignore V3. You should be able to figure it out from this. If not I'm not sure I can help...

Did you upload the wrong file ? i didnt see it it is related to
http://i.imgur.com/RWZ5odq.png this case , can you change the RQQ to k(Q^2) , i am not comfortable with RQQ and dir ? what does dir mean?

It's related to the other example. Ignore dir, that was for my own use to decide whether to add or subtract. I'm afraid I have my own work to do and have already spent too much time on this.

which example do you refer to ?

Spreadsheet attached. Ignore V3. You should be able to figure it out from this. If not I'm not sure I can help...

Just use the final values from your previous iteration.

In fact, just use uncorrected values. It will make your life easier.

so ,, based on your working , if we split up the network into 2 loops , then we would 2 values of flow rate at junction BD , right ? the first is the corrected value in the first loop which is to be used in the first iteration in second loop , then we would also get the corrected value from the second loop ,
so we should get the corrected value from the second loop to do the ieration for the second trial at first loop ?

If I'm following you right then yes, that is correct.

is it possible to have the value of delta Q become larger and then become smaller again in the iteration ?