AS Physics help please

Hi all,

Could anyone explain why the answer is 6 please?

Thank you!

ok so, first step:
the reading when switch is closed is 3 ohms for the resistance and 24v
2nd : as the switch is closed the resistance changes ( product over sum it is 2.25 ohms)
3rd: 3 / 2.25 is 0.75
4th:
0.75 x 24 = 18
5th: 24 - 18 = 6

ok so, first step:
the reading when switch is closed is 3 ohms for the resistance and 24v
2nd : as the switch is closed the resistance changes ( product over sum it is 2.25 ohms)
3rd: 3 / 2.25 is 0.75
4th:
0.75 x 24 = 18
5th: 24 - 18 = 6

Was the load connexted in parallel? I couldnt tell

you would assume it was set up reguarly

Thank you for your reply

What does "product over sum" mean?

I thought total resistance would be 12ohms

Follow a logical thought pattern

I couldnt tell from the question that it was in parallel so i assumed it was in series so i added the resistance

when you have two resistances in parallel, you do the product ( times them together ) nd then divide it by the sum ( add them up ) for the total resistance

Okay so this is the same as doing (1/A+1/B)^-1 if "A" and "B" were to be two resistances in parallel.

And so why would you calculate 0.75?