Hi, for question 9e, on the second past paper: The only information we have is to get from 10 degrees to 60 degrees, the volume of trapped air goes from 19.5 to 23.0. We need to first find out a link between the temperature and the volume of trapped air. The first step is understand that an increase of 50 degrees (from 10 to 60 degrees) means that there is also an increase of the volume of trapped air by 3.5 cm cubed (from 19.5 to 23.0). Then we divide 3.5 by 50, which is 0.07 - this is so that we work out the volume of trapped air when the temperature is 1 degrees C. Then we do 19.5 / 0.07 which is 278.6 degrees - we are dividing the volume of trapped air at 10 degrees by the volume of trapped air at 1 degrees Then do 10 degrees minus the 278.6 degrees we worked out earlier to find it out the volume of trapped air at 10 degrees to get -268.6 degrees. This is from my understanding of the question and I apologise if I haven't been clear, but I hope you now understand the question! Good luck with your exams!!