The Student Room Group

How would I solve this equation?

2(6 - x) = 3(2x + 2)

I got x = 0.75
Expand brackets: 12-2x=6x+6
Solve as usual:
12 = 8x - 6. (Add 2x to each side)
18 = 8x. (Add 6 to each side)
x = 18/8
x = 2.25



Posted from TSR Mobile
Reply 2
In my answer book it says -3?
Original post by francesco_16
Expand brackets: 12-2x=6x+6
Solve as usual:
12 = 8x - 6. (Add 2x to each side)
18 = 8x. (Add 6 to each side)
x = 18/8
x = 2.25


Thanks but in my answer book it says -3 is x? Strange



Posted from TSR Mobile
Reply 3
Original post by Jack_Tomlin

2(6 - x) = 3(2x + 2)

I got x = 0.75


1. Expand brackets
Gives 12 - 2x = 6x +6

2. Put constants on one side, variables on the other
Gives 6 = 8x

3. Divide by the variable coefficient
Gives x = 0.75.

The book is either wrong or you have misread the question.
Reply 4
Sorry you was right I read it wrong I must have been tired last night :smile: The question was actually 2(6 - x) = 3(2x + 12)
Original post by JLegion
1. Expand brackets
Gives 12 - 2x = 6x +6

2. Put constants on one side, variables on the other
Gives 6 = 8x

3. Divide by the variable coefficient
Gives x = 0.75.

The book is either wrong or you have misread the question.
Reply 5
image.jpgIs this right now?
Original post by JLegion
1. Expand brackets
Gives 12 - 2x = 6x +6

2. Put constants on one side, variables on the other
Gives 6 = 8x

3. Divide by the variable coefficient
Gives x = 0.75.

The book is either wrong or you have misread the question.
Reply 6
Original post by Jack_Tomlin
image.jpgIs this right now?


Perfect :smile:

Quick Reply

Latest