The Student Room Group

How is this algebraically possible? (C3 Differentiation, Product Rule)

Can someone please guide me through this? I don't know how it has been simplified.

Thanks.
(edited 7 years ago)
Reply 1
Original post by ManLike007
Can someone please guide me through this? I don't know how it has been simplified.

Thanks.


Clearly (1 + 3x)^4 is a factor of both expressions being added on the first line, so you "take it out"
Reply 2
Original post by 1 8 13 20 42
Clearly (1 + 3x)^4 is a factor of both expressions being added on the first line, so you "take it out"


I don't quite understand what you mean.
(edited 7 years ago)
Reply 3
Original post by ManLike007
What do you mean? I still can't get my head around this.


ab + ac = a(b + c) right

you have

15x(1+3x)4+(1+3x)5=(1+3x)4(15x)+(1+3x)4(1+3x) \displaystyle 15x {(1 + 3x)}^4 + {(1 + 3x)}^5 = {(1 + 3x)}^4 (15x) + {(1 + 3x)}^4 (1 + 3x)

then use the general factorisation above..
Reply 4
Original post by 1 8 13 20 42
ab + ac = a(b + c) right

you have

15x(1+3x)4+(1+3x)5=(1+3x)4(15x)+(1+3x)4(1+3x) \displaystyle 15x {(1 + 3x)}^4 + {(1 + 3x)}^5 = {(1 + 3x)}^4 (15x) + {(1 + 3x)}^4 (1 + 3x)

then use the general factorisation above..


ok that makes much more sense now. Thanks for your time, massive thanks.
(edited 7 years ago)

Quick Reply

Latest