oxidation numbers in chemistry
Okay guys am having a serious problem in calculating the oxidation numbers of certain elements in a compound....
e.g what is the oxidation number of POTASSIUM in the compound potassium permanganate?(KMnO4)
if there are any important procedures that need to be taken care of, please show them up
e.g what is the oxidation number of POTASSIUM in the compound potassium permanganate?(KMnO4)
if there are any important procedures that need to be taken care of, please show them upThe potassium is +1 as it is In group one. The potassium can take several oxidation states and is the one that normally needs working out whereas almost always, Oxygen is 2- and group ones are +1.
Original post by Ewanclementson
The potassium is +1 as it is In group one. The potassium can take several oxidation states and is the one that normally needs working out whereas almost always, Oxygen is 2- and group ones are +1.
Yeah I get that, what about of Manganese?
Hello,
KMnO4:
1)Split the compound up into its basic elements so K, Mn, O4
2)Oxygen's oxidation number is 2- but because there are 4 oxygen atoms then overall for O4 the charge is 8-
3)Potassium is in group 1 therefore it's oxidation number is 1+
4)As this compound has no overall charge the oxidation number overall should be 0.
5) So far you have 8- and 1+
6) Therefore Mn's oxidation number is 7+ so that all the charges cancel each other out.
Hope that makes sense!
KMnO4:
1)Split the compound up into its basic elements so K, Mn, O4
2)Oxygen's oxidation number is 2- but because there are 4 oxygen atoms then overall for O4 the charge is 8-
3)Potassium is in group 1 therefore it's oxidation number is 1+
4)As this compound has no overall charge the oxidation number overall should be 0.
5) So far you have 8- and 1+
6) Therefore Mn's oxidation number is 7+ so that all the charges cancel each other out.
Hope that makes sense!
okay now I get the sense of it, Thanks a lot
Original post by luckytharm
Hello,
KMnO4:
1)Split the compound up into its basic elements so K, Mn, O4
2)Oxygen's oxidation number is 2- but because there are 4 oxygen atoms then overall for O4 the charge is 8-
3)Potassium is in group 1 therefore it's oxidation number is 1+
4)As this compound has no overall charge the oxidation number overall should be 0.
5) So far you have 8- and 1+
6) Therefore Mn's oxidation number is 7+ so that all the charges cancel each other out.
Hope that makes sense!
KMnO4:
1)Split the compound up into its basic elements so K, Mn, O4
2)Oxygen's oxidation number is 2- but because there are 4 oxygen atoms then overall for O4 the charge is 8-
3)Potassium is in group 1 therefore it's oxidation number is 1+
4)As this compound has no overall charge the oxidation number overall should be 0.
5) So far you have 8- and 1+
6) Therefore Mn's oxidation number is 7+ so that all the charges cancel each other out.
Hope that makes sense!
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